3x^2-27x-1200=0

Solution for 3x^2-27x-1200=0 equation:

3x^2-27x-1200=0

a = 3; b = -27; c = -1200;
Δ = b2-4ac
Δ = -272-4·3·(-1200)
Δ = 15129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15129}=123$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-123}{2*3}=\frac{-96}{6}
=-16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+123}{2*3}=\frac{150}{6}
=25
$